x^2+50(x)-336=0

Solution for x^2+50(x)-336=0 equation:

x^2+50(x)-336=0

a = 1; b = 50; c = -336;
Δ = b2-4ac
Δ = 502-4·1·(-336)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-62}{2*1}=\frac{-112}{2}
=-56
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+62}{2*1}=\frac{12}{2}
=6
$